[Java][Answer] CodingBat Array-1 > make2()

Given 2 int arrays, a and b, return a new array length 2 containing, as much as will fit, the elements from a followed by the elements from b. The arrays may be any length, including 0, but there will be 2 or more elements available between the 2 arrays.

make2([4, 5], [1, 2, 3]) → [4, 5]
make2([4], [1, 2, 3]) → [4, 1]
make2([], [1, 2]) → [1, 2]

Answer 1:

public int[] make2(int[] a, int[] b) {
  if(a.length == 1) return new int[]{a[0],b[0]};
  else if(a.length == 0) return new int[]{b[0],b[1]};
  else return new int[]{a[0],a[1]};
}

Answer 2:

public int[] make2(int[] a, int[] b) {
  int[] myArray = new int[2];
  int aLen = a.length;
  int bLen = b.length;
 
  if (aLen == 0) {
    myArray[0] = b[0];
    myArray[1] = b[1];
    return myArray;
  } else if (aLen == 1 && bLen == 1) {
    myArray[0] = a[0];
    myArray[1] = b[0];
    return myArray;
  } else if (aLen == 1) {
      myArray[0] = a[0];
      myArray[1] = b[0];
      return myArray; 
  } else {
      myArray[0] = a[0];
      myArray[1] = a[1];
      return myArray;
  }
}

Reference

http://www.javaproblems.com/2013/11/java-array-1-make2-codingbat-solution.html