[Java][Answer] CodingBat Array-2 > sum67()

Return the sum of the numbers in the array, except ignore sections of numbers starting with a 6 and extending to the next 7 (every 6 will be followed by at least one 7). Return 0 for no numbers.

sum67([1, 2, 2]) → 5
sum67([1, 2, 2, 6, 99, 99, 7]) → 5
sum67([1, 1, 6, 7, 2]) → 4

Answer 1:

public int sum67(int[] nums) {
  int sum  = 0;
  boolean stop = false;
  for(int i=0;i<nums.length;i++){
      if(nums[i]==6) stop=true;
      if(!stop)sum += nums[i];
      if(nums[i]==7) stop=false;    
  }
  return sum;
}

Answer 2:

public int sum67(int[] nums) {
  int sum = 0;
  boolean stop = false;
 
  for (int i = 0; i < nums.length; i++) {
    if (nums[i] == 6)
      stop = true;
    if (stop == false)
      sum += nums[i];
    if (nums[i] == 7 && stop == true)
      stop = false;
  }
  return sum;
}

Reference
http://www.javaproblems.com/2013/11/java-array-2-sum67-codingbat-solution.html