[Java][Answer] CodingBat Array-2 > bigDiff()

Given an array length 1 or more of ints, return the difference between the largest and smallest values in the array. Note: the built-in Math.min(v1, v2) and Math.max(v1, v2) methods return the smaller or larger of two values.

bigDiff([10, 3, 5, 6]) → 7
bigDiff([7, 2, 10, 9]) → 8
bigDiff([2, 10, 7, 2]) → 8

Answer 1:

public int bigDiff(int[] nums) {
  int max = nums[0];
  int min = nums[0];
  for(int i=0;i<nums.length;i++){
    max = Math.max(max, nums[i]);
    min = Math.min(min, nums[i]);
  }
  return max-min;
}