[Java][Answer] CodingBat Array-2 > countEvens()

Return the number of even ints in the given array. Note: the % "mod" operator computes the remainder, e.g. 5 % 2 is 1.

countEvens([2, 1, 2, 3, 4]) → 3
countEvens([2, 2, 0]) → 3
countEvens([1, 3, 5]) → 0

Answer 1:

public int countEvens(int[] nums) {
  int evenCount = 0;
  for(int i=0;i<nums.length;i++){
    if(nums[i]%2==0) evenCount++;
  }
  return evenCount;
}